32x^2-15x-47=0

Solution for 32x^2-15x-47=0 equation:

32x^2-15x-47=0

a = 32; b = -15; c = -47;
Δ = b2-4ac
Δ = -152-4·32·(-47)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-79}{2*32}=\frac{-64}{64}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+79}{2*32}=\frac{94}{64}
=1+15/32
$